x^2+25x-3750=0

Solution for x^2+25x-3750=0 equation:

x^2+25x-3750=0

a = 1; b = 25; c = -3750;
Δ = b2-4ac
Δ = 252-4·1·(-3750)
Δ = 15625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15625}=125$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-125}{2*1}=\frac{-150}{2}
=-75
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+125}{2*1}=\frac{100}{2}
=50
$